BergEC-jl/OSBRACKETS/allosbrac.f90

452 lines
19 KiB
Fortran
Executable File

SUBROUTINE ALLOSBRAC(NQMAX,LMIN,LMAX,CO,SI,BRAC)
! COMMENTS ON USE:
!---------------------------------------------------------------------------------------------------------------------------------------
! THE OSCILLATOR BRACKETS <N1P,L1P,N2P,L2P|N1,L1,N2,L2>_L^\VARPHI ARE
! CALCULATED HERE. THIS IS DONE WITH THE HELP OF EQS. (18), (20)-TYPE, AND (22) IN
! THE ACCOMPANYING CPC PAPER. THE QUANTITIES L1, L2, L1P, AND L2P IN THE ABOVE
! DEFINITION OF THE BRACKETS ARE THE PARTIAL ANGULAR MOMENTA, L IS THE TOTAL
! ANGULAR MOMENTUM, AND N1, N2, N1P, N2P ARE THE RADIAL QUANTUM NUMBERS.
! IN THE NOTATION LIKE L1P, ETC., "P" SYMBOLIZES "PRIMED" HERE AND BELOW.
! THE SUBROUTINE RETURNS THE ARRAY OF ALL THE BRACKETS SUCH THAT
! L1+L2+2*(N1+N2).LE.NQMAX, LMIN \LE L \LE LMAX, AND THE BRACKETS PERTAIN TO STATES
! OF THE SAME PARITY (-1)^(L1+L2) WHICH IS THE PARITY OF NQMAX.
! THE L1, L2, L1P, AND L2P ORBITAL MOMENTA ARE EXPRESSED IN THE SUBROUTINE IN
! TERMS OF THE M, N, MP, AND NP VARIABLES DEFINED AS FOLLOWS
! M=(L1+L2-L-NN)/2, N=(L1-L2+L-NN)/2, MP=(L1P+L2P-L-NN)/2, NP=(L1P-L2P+L-NN)/2
! WHERE NN EQUALS 0 OR 1 WHEN, RESPECTIVELY, NQMAX-L IS EVEN OR ODD. ONE THEN HAS
! L1 = M+N+NN, L2 = M-N+L, L1P = MP+NP+NN, L2P = MP-NP+L.
! WHEN L1, L2, L1P AND L2P TAKE ALL THE VALUES ALLOWED AT GIVEN L AND GIVEN PARITY
! THE N AND NP VARIABLES TAKE ALL THE INTEGER VALUES FROM ZERO UP TO L-NN AND
! THE M AND MP VARIABLES TAKE ALL THE INTEGER VALUES FROM ZERO UP TO (NQMAX-L-NN)/2.
! ONE ALSO HAS NQ=2*(M+N1+N2)+L+NN=2*(MP+N1P+N2P)+L+NN.
! ALL THE PARAMETERS OF THE SUBROUTINE BUT BRAC ARE INPUT ONES. THE MEANING
! OF THE NQMAX, LMIN, AND LMAX PARAMETERS IS SEEN FROM THE ABOVE DESCRIPTION.
! THE BRAC PARAMETER DESIGNATES THE ARRAY OF OUTPUT BRACKETS. IT IS OF THE FORM
! BRAC(NP,N1P,MP,N1,N2,N,M,L) . (AS SAID ABOVE, L1=L1(N,M), L2=L2(N,M), L1P=L1P(NP.MP),
! AND L2P=L2P(NP,MP). THE QUANTITY N2P IS DETERMINED BY THE EQUALITY
! MP+N1P+N2P=M+N1+N2.) THE ORDER OF THE ARGUMENTS OF BRAC CORRESPONDS TO
! NESTING OF THE LOOPS AT ITS COMPUTATION.
! THE ROUTINE PARAMETERS CO AND SI ARE AS FOLLOWS, CO = COS(PHI) AND SI = SIN(PHI).
! THESE QUANTITIES DEFINE THE PSEUDO(!!!)ORTHOGONAL TRANSFORMATION
! XI1P = CO*XI1+SI*XI2, XI2P = SI*XI1-CO*XI2.
! (BRACKETS PERTAINING TO THE CASE OF THE ORTHOGONAL TRANSFORMATION
! XI1P = CO*XI1+SI*XI2, XI2P = -SI*XI1+CO*XI2 ARE SIMPLY EXPRESSED IN TERMS OF
! THOSE CALCULATED IN THE PRESENT PROGRAM, SEE THE ACCOMPANYING CPC PAPER.
! THE MEANING OF THE ARRAYS, OTHER THAN BRAC, ENTERING THE DIMENSION LIST IS AS
! FOLLOWS. B IS A SUBSIDIARY ARRAY TO PERFORM THE RECURSION.
! FAC(I)=I!, DFAC(I)=(2I+1)!!, AND DEFAC(I)=(2I)!!. RFAC(I)=SQRT((2I)!)/I!
! THESE ARRAYS ARE PRODUCED BY THE "ARR" ROUTINE WHICH IS CALLED FROM THE PRESENT
! ROUTINE AND WHICH IS CONTAINED IN THE PRESENT FILE. THE SET UPPER BOUNDS OF THESE
! ARRAYS ARE SUFFICIENT FOR THE COMPUTATION. THESE ARRAYS ARE USED IN THE PRESENT
! ROUTINE AND IN THE "FLPHI" ROUTINE.
! THE A ARRAY IS A(N,L)=(-1)**N/SQRT(DEFAC(N)*DFAC(N+L)). IT APPEARS BOTH IN THE N1=N2=0
! BRACKETS AND IN THE RELATION BETWEEN THE < | > AND [ | ] TYPE BRACKETS.
! THE BI ARRAY IS BI(M,N)=FAC(N)/[FAC(M)*FAC(N-M)]. IT ENTERS THE 3J SYMBOLS. IT IS USED
! IN THE "FLPHI" ROUTINE AND IN THE FUNCTION WIGMOD.
! THE FL(NP,MP,N) ARRAY REPRESENTS THE QUANTITY
! [(2*L1P+1)*(2*L2P+1)]^{1/2}*F_L^VARPHI WHERE F_L^VARPHI IS GIVEN BY EQ. (23) IN THE
! ACCOMPANYING CPC PAPER. THIS ARRAY IS PRODUCED IN ADVANCE BY THE
! "FLPHI" ROUTINE WHICH IS CALLED FROM THE PRESENT ROUTINE AND WHICH IS
! CONTAINED IN THE PRESENT FILE. THE VARIABLES MP, NP, AND N ARE DEFINED ABOVE ALONG
! WITH THEIR UPPER BOUNDS.
! THE PSIP(P,Q) AND PSIM(P,Q) ARRAYS REPRESENT THE QUANTITIES (4) IN THE ACCOMPANYING
! CPC PAPER. THEY ARE PRODUCED IN ADVANCE BY THE "COEFREC" ROUTINE
! WHICH IS CALLED FROM THE PRESENT ROUTINE AND WHICH IS CONTAINED IN THE PRESENT
! FILE. THEIR ARGUMENTS P AND Q TAKE THE VALUES L1P, L1P+/-1 AND L2P, L2P+/-1,
! RESPECTIVELY. THE BOUNDS OF THE PSIP AND PSIM ARRAYS ARE SUCH THAT ALL THE P AND Q
! VALUES REQUIRED TO PERFORM THE RECURSION ARE PROVIDED.
! THE MENTIONED "FLPHI" ROUTINE USES THE FUNCTION WIGMOD WHICH IS ALSO CONTAINED
! IN THE PRESENT FILE.
!----------------------------------------------------------------------------------------------------------------------------------------
DOUBLE PRECISION BRAC,FL,PSIP,PSIM,A,FAC,DFAC,DEFAC,RFAC,BI,CO,SI,T,CO2,SI2,SC,FA,&
PLFACT,D2L12P,TN,PA,S,FA1,FA2
DIMENSION&
BRAC(0:LMAX,0:(NQMAX-LMIN)/2,0:(NQMAX-LMIN)/2,0:(NQMAX-LMIN)/2,&
0:(NQMAX-LMIN)/2,0:LMAX,0:(NQMAX-LMIN)/2,LMIN:LMAX),&
! THE ARRAY IS OF THE FORM BRAC(NP,N1P,MP,N1,N2,N,M,L)
FL(0:LMAX,0:(NQMAX-LMIN)/2,0:LMAX),&
PSIP((NQMAX+LMAX)/2+1,(NQMAX+LMAX)/2+1),&
PSIM((NQMAX+LMAX)/2+1,(NQMAX+LMAX)/2+1),A(0:NQMAX/2+1,0:NQMAX),&
FAC(0:2*NQMAX+1),DFAC(0:NQMAX+1),DEFAC(0:NQMAX/2+1),RFAC(0:NQMAX),&
BI(0:2*NQMAX+1,0:2*NQMAX+1)
IF (NQMAX.GT.84) THEN
WRITE(6,*)'IN THE R(*8) COMPUTATION NQMAX SHOULD NOT EXCEED 84'
STOP
ENDIF
IF (CO.EQ.0.D0.OR.SI.EQ.0.D0) THEN
WRITE(6,*)'THE PROGRAM IS OF NO USE AT ZERO COS(PHI) OR SIN(PHI) VALUES'
WRITE(6,*)'COS(PHI)=',CO,' SIN(PHI)=',SI
STOP
ENDIF
IF (NQMAX.LT.LMAX) THEN
WRITE(6,*)'NQMAX=',NQMAX,' L=',LMAX
WRITE(6,*)'L SHOULD NOT EXCEED NQMAX'
STOP
ENDIF
T=SI/CO
CO2=CO**2
SI2=SI**2
SC=SI*CO
CALL ARR(FAC,DFAC,DEFAC,RFAC,NQMAX)
CALL COE(2*NQMAX+1,FAC,BI)
! THE A_{NL} ARRAY:
DO NI=0,NQMAX/2+1
NA=NI-2*(NI/2)
K=1
IF(NA.EQ.1)K=-1
DO LI=0,NQMAX-NI
A(NI,LI)=K/SQRT(DEFAC(NI)*DFAC(NI+LI))
ENDDO
ENDDO
! BRACKETS [N_1'L_1'N_2'L_2'|0L_10L_2]_L^\PHI TO START THE RECURSION, EQ. (22) IN
! THE ACCOMPANYING CPC PAPER.
! THESE BRACKETS ARE REPRESENTED AS BRAC(NP,N1P,MP,0,0,N,M,L).
! SUBSIDIARY QUANTITIES:
DO L=LMIN,LMAX
CALL FLPHI(NQMAX,LMAX,LMIN,L,T,BI,RFAC,FL)
! THIS SUBROUTINE PRODUCES THE ARRAY FL USED BELOW.
NQML=NQMAX-L
NQMLD2=NQML/2
NN=NQML-2*(NQMLD2)
CALL COEFREC((NQMAX+LMAX)/2+1,L,NN,NQMAX,PSIP,PSIM)
NMAX=L-NN
MMAX=(NQML-NN)/2
DO M=0,MMAX
DO N=0,NMAX
L1=M+N+NN
L2=M-N+L
L1L2=L1+L2
L1L2ML=L1L2-L
FA=SQRT((2.D0*L1+1)*(2*L2+1))*CO**L1L2
PLFACT=SQRT(FAC(L1L2+L+1)*FAC(L1L2ML))
! COMPUTATION OF THE N1=N2=0 BRACKETS. THEY ARE REPRESENTED AS
! BRAC(NP,N1P,MP,0,0,N,M,L).
MPMAX=(L1L2ML-NN)/2
DO MP=0,MPMAX
L12P=2*MP+L+NN
! THIS IS BY DEFINITION, L12P=L1P+L2P
D2L12P=1.D0/2.D0**L12P
N12P=MPMAX-MP
! INDEED, 2*N12P=2*(N1P+N2P)=NQ-L12P. FOR THE BRACKETS WE COMPUTE NOW
! WE HAVE NQ=L1L2. THEN 2*N12P=L1L2-L12P. SINCE L1L2=2*MPMAX-L-NN AND
! L12P=2*MP+L+NN, ONE GETS N12P=MPMAX-MP.
DO N1P=0,N12P
N1PA=N1P-2*(N1P/2)
IF (N1PA.EQ.0) THEN
K=1
ELSE
K=-1
ENDIF
! K=(-1)**N1P
N2P=N12P-N1P
TN=T**N12P*K
DO NP=0,NMAX
L1P=MP+NP+NN
L2P=L12P-L1P
! BY DEFINITION ONE ALSO HAS: L2P=L2P(MP,NP)=MP-NP+L
PA=A(N1P,L1P)*A(N2P,L2P)
BRAC(NP,N1P,MP,0,0,N,M,L)=FL(NP,MP,N)*FA*TN*D2L12P&
*PLFACT*PA*PA
ENDDO ! NP
ENDDO ! N1P
ENDDO ! MP
! RECURSION TO OBTAIN THE GENERAL FORM BRACKETS
! [N_1'L_1'N_2'L_2'|N_1L_1N_2L_2]_L^\PHI.
N12MAX=(NQMAX-L1L2)/2
MPMAX0=MPMAX
! THE N1=0, N2-1-->N2 RECURSION, EQ. (20) IN THE ACCOMPANYING CPC PAPER WITH THE
! MODIFICATION POINTED OUT THERE:
DO N2=1,N12MAX
MPMAX=MPMAX+1
! THIS MPMAX VALUE IS (NQ-L-NN)/2 WHERE NQ=L1+L2+2*N2.
DO MP=0,MPMAX
N12P=MPMAX-MP
DO N1P=0,N12P
! MP=(L1P+L2P-L-NN)/2. THEREFORE, N12P=MPMAX-MP=(NQ-L1P-L2P)/2=N1P+N2P.
DO NP=0,NMAX
L1P=MP+NP+NN
L2P=MP-NP+L
S=0.D0
! BELOW THE RESTRICTIONS ARE IMPOSED ON THE BRAC ARRAY ENTERING THE RIGHT-HAND
! SIDE OF THE RECURRENCE FORMULAE. THIS ARRAY IS OF THE FORM BRAC(K1,K2,K3,...) WHERE
! K1=K1(NP), K2=N2(N1P), AND K3=K3(MP). NAMELY, K1=NP, OR NP+1, OR NP-1;
! K2=N1P OR N1P-1; K3=MP, OR MP-1, OR MP+1. (THE COMBINATION K2=N1P AND K3=MP+1
! DOES NOT ARISE IN THE RECURRENCE FORMULAE.) THE QUANTITIES K1, K2, AND K3
! REPRESENT, RESPECTIELY, NP, N1P, AND MP VALUES AT THE PRECEDING STAGE OF THE
! RECURSION. THE RESTRICTIONS ENSURE THAT K1, K2, AND K3 RANGE WITHIN THE LIMITS
! PERTAINING TO THE BRAC ARRAY OBTAINED AT THAT PRECEDING STAGE OF THE RECURSION.
! THUS K1, K2, AND K3 SHOULD BE NON-NEGATIVE. THEREFORE, WHEN K1=NP-1 THE VALUE
! NP=0 IS TO BE EXCLUDED, WHEN K2=N1P-1 THE VALUE N1P=0 IS TO BE EXCLUDED, AND
! WHEN K3=MP-1 THE VALUE MP=0 IS TO BE EXCLUDED.
! FURTHERMORE, IT SHOULD BE K1 \LE NMAX AND AT THE SAME TIME ONE HAS NP \LE NMAX.
! THEREFORE, WHEN K1=NP+1 THE VALUE NP=NPMAX IS TO BE EXCLUDED.
! IN ADDITION, IT SHOULD BE K2+K3 \LE MPMAX-1 WHILE ONE HAS N1P+MP \LE MPMAX. WHEN
! K2=N1P AND K3=MP-1, OR K2=N1P-1 AND K3=MP-1, OR K2=N1P-1 AND K3=MP ONE
! AUTOMATICALLY HAS N1P+MP \LE MPMAX. THEREFORE, IN THESE CASES THE CONDITION
! K2+K3 \LE MPMAX-1 DOES NOT CREATE ANY RESTRICTIONS.
! BUT WHEN K2=N1P AND K3=MP, OR K2=N1P-1 AND K3=MP+1 THE CASE N1P+MP=MPMAX
! IS TO BE FORBIDDEN.
! IN THE RECURRENCE FORMULAE BELOW THE DESCRIBED RESTRICTIONS ARE
! IMPOSED.
IF (MP.NE.0) S=BRAC(NP,N1P,MP-1,0,N2-1,N,M,L)*PSIP(L1P,L2P)
IF (N1P.NE.0.AND.N1P.NE.N12P) S=S+&
BRAC(NP,N1P-1,MP+1,0,N2-1,N,M,L)*PSIP(L1P+1,L2P+1)
! RECALL THAT N12P=MPMAX-MP.
IF (NP.NE.NMAX.AND.N1P.NE.0) S=S-&
BRAC(NP+1,N1P-1,MP,0,N2-1,N,M,L)*PSIM(L1P+1,L2P)
IF (NP.NE.0.AND.N1P.NE.N12P) S=S-&
BRAC(NP-1,N1P,MP,0,N2-1,N,M,L)*PSIM(L1P,L2P+1)
S=S*SC
IF (N1P.NE.0) S=S+BRAC(NP,N1P-1,MP,0,N2-1,N,M,L)*SI2
IF (N1P.NE.N12P) S=S+BRAC(NP,N1P,MP,0,N2-1,N,M,L)*CO2
BRAC(NP,N1P,MP,0,N2,N,M,L)=S
ENDDO ! NP
ENDDO ! N1P
ENDDO ! MP
ENDDO ! N2
! N1-1-->N1 RECURSION, EQ. (20) IN THE ACCOMPANYING CPC PAPER:
DO N2=0,N12MAX
MPMAX=MPMAX0+N2
! THE CURRENT MPMAX VALUE IS (NQ-L-NN)/2=MPMAX0+N2 SINCE NQ=L1+L2+2*N2.
! THE RECURSION:
DO N1=1,N12MAX-N2
MPMAX=MPMAX+1
! THE CURRENT MPMAX VALUE IS (NQ-L-NN)/2 AND NQ=L1+L2+2*N2+2*N1.
DO MP=0,MPMAX
N12P=MPMAX-MP
DO N1P=0,N12P
! MP=(L1P+L2P-L-NN)/2. THEREFORE, N1PMAX=MPMAX-MP=(NQ-L1P-L2P)/2=N1P+N2P.
DO NP=0,NMAX
L1P=MP+NP+NN
L2P=MP-NP+L
S=0.D0
IF (MP.NE.0) S=BRAC(NP,N1P,MP-1,N1-1,N2,N,M,L)*PSIP(L1P,L2P)
IF (N1P.NE.0.AND.N1P.NE.N12P) S=S+&
BRAC(NP,N1P-1,MP+1,N1-1,N2,N,M,L)*PSIP(L1P+1,L2P+1)
IF (NP.NE.NMAX.AND.N1P.NE.0) S=S-&
BRAC(NP+1,N1P-1,MP,N1-1,N2,N,M,L)*PSIM(L1P+1,L2P)
IF (NP.NE.0.AND.N1P.NE.N12P) S=S-&
BRAC(NP-1,N1P,MP,N1-1,N2,N,M,L)*PSIM(L1P,L2P+1)
! THESE RELATIONS ARE THE SAME AS THE CORRESPONDING ONES ABOVE.
S=-S*SC
IF (N1P.NE.0) S=S+BRAC(NP,N1P-1,MP,N1-1,N2,N,M,L)*CO2
IF (N1P.NE.N12P) S=S+BRAC(NP,N1P,MP,N1-1,N2,N,M,L)*SI2
! THESE RELATIONS ARE THE SAME AS THE CORRESPONDING ONES ABOVE.
BRAC(NP,N1P,MP,N1,N2,N,M,L)=S
ENDDO ! NP
ENDDO ! N1P
ENDDO ! MP
ENDDO ! N1
ENDDO ! N2
! RENORMALIZATION OF THE BRACKETS, EQ. (18) IN THE ACCOMPANYING CPC PAPER:
DO N2=0,N12MAX
MPMAX1=MPMAX0+N2
DO N1=0,N12MAX-N2
MPMAX=MPMAX1+N1
FA1=A(N1,L1)*A(N2,L2)
DO MP=0,MPMAX
N12P=MPMAX-MP
DO N1P=0,MPMAX-MP
N2P=N12P-N1P
DO NP=0,NMAX
L1P=MP+NP+NN
L2P=MP-NP+L
FA2=A(N1P,L1P)*A(N2P,L2P)
BRAC(NP,N1P,MP,N1,N2,N,M,L)=BRAC(NP,N1P,MP,N1,N2,N,M,L) &
*FA1/FA2
ENDDO ! NP
ENDDO ! N1P
ENDDO ! MP
ENDDO ! N1
ENDDO ! N2
ENDDO ! N
ENDDO ! M
ENDDO ! L
RETURN
END
SUBROUTINE ARR(FAC,DFAC,DEFAC,RFAC,NQMAX)
! FAC(I), DFAC(I),DEFAC(I), AND RFAC(I) ARE, RESPECTIVELY, THE QUANTITIES
! I!, (2I+1)!!, (2I)!!, AND SQRT((2*I)!)/I!
DOUBLE PRECISION FAC,DFAC,DEFAC,RFAC
DIMENSION FAC(0:2*NQMAX+1),DFAC(0:NQMAX+1),DEFAC(0:NQMAX/2+1),RFAC(0:NQMAX)
FAC(0)=1.D0
DFAC(0)=1.D0
DEFAC(0)=1.D0
RFAC(0)=1.D0
DO I=1,2*NQMAX+1
FAC(I)=FAC(I-1)*I
ENDDO
DO I=1,NQMAX+1
DFAC(I)=DFAC(I-1)*(2*I+1)
ENDDO
DO I=1,NQMAX/2+1
DEFAC(I)=DEFAC(I-1)*2*I
ENDDO
DO I=1,NQMAX
RFAC(I)=RFAC(I-1)*2*SQRT(1-0.5D0/I)
ENDDO
RETURN
END
SUBROUTINE FLPHI(NQMAX,LMAX,LMIN,L,T,BI,RFAC,FL)
! PROVIDES THE QUANTITY SQRT((2L1P+1)*(2L2P+1))*F_L^\VARPHI, SEE EQ. (23) IN THE
! ACCOMPANYING PAPER, IN THE FORM OF THE FL ARRAY.
! USES THE FUNCTION WIGMOD.
! THIS FLPHI DIFFERS FROM THAT IN THE OTHER FILE osbrac.f90.
DOUBLE PRECISION BI,RFAC,FL,T,T2,SQP,F,WIGMOD,z
DIMENSION&
FL(0:LMAX,0:(NQMAX-LMIN)/2,0:LMAX),BI(0:2*NQMAX+1,0:2*NQMAX+1),RFAC(0:NQMAX)
! THE OUTPUT IS FL(NP,MP,N) WHERE MP=(L1P+L2P-L-NN)/2, L1P+L2P=L1T+L2T,
! NP=(L1P-L2P+L-NN)/2, AND N=(L1-L2+L-NN)/2, L1-L2=L1T-L2T.
T2=T*T
NQMAL=NQMAX-L
MPMAX=NQMAL/2
NN=NQMAL-2*MPMAX
LMNN=L-NN
LL3=2*L
DO N=0,LMNN
L1ML2=2*N-LMNN
DO MP=0,MPMAX
L1PL2P=2*MP+L+NN
DO NP=0,LMNN
L1PML2P=2*NP-LMNN
L1P=(L1PL2P+L1PML2P)/2
L2P=(L1PL2P-L1PML2P)/2
M3=L2P-L1P
SQP=SQRT((2*L1P+1.D0)*(2*L2P+1))
L1T=(L1PL2P+L1ML2)/2
L2T=(L1PL2P-L1ML2)/2
N3=L1T+L2T-L
IMIN=ABS(L1T-L1P)
IMAX=MIN(L1P+L1T,L2P+L2T)
NAL1=(L1T+L1P-IMIN)/2
NAL2=(L1T-L1P+IMIN)/2
NAL3=(L2T-L2P+IMIN)/2
NAL4=(L2T+L2P-IMIN)/2
NAL4P=NAL4-2*(NAL4/2)
F=0.D0
z=t**imin
if(nal4p.ne.0)z=-z
DO I=IMIN,IMAX,2
F=F+RFAC(NAL1)*RFAC(NAL2)*RFAC(NAL3)*RFAC(NAL4)*&
WIGMOD(L1T,L2T,L,L1P-I,I-L2P,BI,2*NQMAX+1)*z
NAL1=NAL1-1
NAL2=NAL2+1
NAL3=NAL3+1
NAL4=NAL4-1
z=-z*t2
ENDDO
FL(NP,MP,N)=F*SQRT((2*L1P+1)*(2*L2P+1)&
*BI(L1T+L-L2T,2*L1T)*BI(N3,2*L2T)/((LL3+1)*BI(N3,L1T+L2T+L+1)*BI(L+M3,LL3)))
ENDDO
ENDDO
ENDDO
RETURN
END
FUNCTION WIGMOD(L1,L2,L3,M1,M2,BI,NMAX)
! THE 3J SYMBOL IN TERMS OF BINOMIAL COEFFICIENTS WITHOUT THE FACTOR
! SQRT(F) WHERE F IS AS FOLLOWS,
! F=BI(L1+L3-L2,2*L1)*BI(N3,2*L2)/((LL3+1)*BI(N3,L1+L2+L3+1)*BI(L3+M3,LL3))
! WITH N3=L1+L2-L3, LL3=2*L3, AND M3=-M1-M2.
DOUBLE PRECISION WIGMOD,BI,S
DIMENSION BI(0:NMAX,0:NMAX)
M3=-M1-M2
N3=L1+L2-L3
LM1=L1-M1
LP2=L2+M2
KMIN=MAX(0,L1-L3+M2,L2-L3-M1)
KMAX=MIN(N3,LM1,LP2)
S=0.d0
NPH=1
DO K=KMIN,KMAX
S=S+NPH*BI(K,N3)*BI(LM1-K,L1+L3-L2)*BI(LP2-K,L2+L3-L1)
NPH=-NPH
ENDDO
WIGMOD=S/SQRT(BI(LM1,2*L1)*BI(LP2,2*L2))
NY=KMIN+L1-L2-M3
NYP=NY-2*(NY/2)
IF(NYP.NE.0)WIGMOD=-WIGMOD
RETURN
END
SUBROUTINE COE(NMAX,FAC,BI)
DOUBLE PRECISION FAC,BI
DIMENSION FAC(0:NMAX),BI(0:NMAX,0:NMAX)
DO N=0,NMAX
DO M=0,N/2
BI(M,N)=FAC(N)/(FAC(M)*FAC(N-M))
BI(N-M,N)=BI(M,N)
ENDDO
ENDDO
RETURN
END
SUBROUTINE COEFREC(MAXCOE,L,NN,NQMAX,PSIP,PSIM)
! CALCULATES THE COEFFICIENTS OF THE RECURSION FORMULA, EQ. (21) IN THE ACCOMPANYING
! CPC PAPER
! MAXCOE EQUALS INT((NQMAX+LMAX)/2)+1 AT CALLS OF THIS ROUTINE.
DOUBLE PRECISION PSIP,PSIM
DIMENSION PSIP(MAXCOE,MAXCOE),PSIM(MAXCOE,MAXCOE)
LP=L+1
LM=L-1
DO M1=1,(NQMAX+L)/2+1
DO M2=1,M1
M1P2=M1+M2
NA=M1P2+L
NNA=NA-2*(NA/2)
M1M2=M1-M2
! CALCULATION OF PSIP. (IN THIS CASE M1 AND M2 REPRESENT, RESPECTIVELY, L1P AND L2P OR
! L1P+1 AND L2P+1.)
IF (NNA.EQ.NN.AND.M1P2.GE.L.AND.M1P2.LE.NQMAX.AND.&
ABS(M1M2).LE.L) THEN
IF (M1P2.GT.LP) THEN
M1P2L=M1P2+L
M1P2ML=M1P2-L
PSIP(M1,M2)=SQRT(M1P2L*(M1P2L+1.D0)*M1P2ML*(M1P2ML-1)/((4*M1*M1-1)&
*(4*M2*M2-1)))
ELSE
PSIP(M1,M2)=0.D0
ENDIF
PSIP(M2,M1)=PSIP(M1,M2)
ENDIF
! CALCULATION OF PSIM. (IN THIS CASE M1 AND M2 REPRESENT, RESPECTIVELY, L1P+1 AND L2P
! OR L2P+1 AND L1P.)
IF (NNA.NE.NN.AND.M1P2.GE.LP.AND.M1P2.LE.NQMAX&
.AND.M1M2.LE.LP.AND.M1M2.GE.-LM) THEN
IF (M1M2.LT.L) THEN
M1M2L=M1M2+L
M1M2ML=M1M2-L
PSIM(M1,M2)=SQRT(M1M2L*(M1M2L+1.D0)*M1M2ML*(M1M2ML-1)/&
((4*M1*M1-1)*(4*M2*M2-1)))
ELSE
PSIM(M1,M2)=0.D0
ENDIF
PSIM(M2,M1)=PSIM(M1,M2)
ENDIF
ENDDO
ENDDO
RETURN
END